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Two Envelopes Paradox

Explore the mathematical illusion where switching always seems better

You are given two envelopes. One has $X$, the other has $2X$. You pick one and see $Y$. The other envelope has either $Y/2$ or $2Y$. The expected value of switching is $(0.5 \times 2Y) + (0.5 \times Y/2) = 1.25Y$. Why is this logic flawed?

Switching Result
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Staying Result
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The Paradox: The mistake is assuming a uniform distribution over all possible values of X. In a real game, the expected values of switching and staying are always equal, as shown by the simulation.

[include_logic file=”two-envelopes-paradox-calculator.php”]

โœ‰๏ธ

Two Envelopes Paradox

Explore the mathematical illusion where switching always seems better

You are given two envelopes. One has $X$, the other has $2X$. You pick one and see $Y$. The other envelope has either $Y/2$ or $2Y$. The expected value of switching is $(0.5 \times 2Y) + (0.5 \times Y/2) = 1.25Y$. Why is this logic flawed?

Switching Result
--
Staying Result
--
The Paradox: The mistake is assuming a uniform distribution over all possible values of X. In a real game, the expected values of switching and staying are always equal, as shown by the simulation.

Placeholder for Two Envelopes Paradox Calculator