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Static Friction Calculator

Calculate structural static equilibrium, center of mass, torque, beam reaction forces, PSI pressure, and stress-strain for static friction.

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Input Statics Parameters

Enter force, distance moment arm, or structural area.

Calculated Torque / Support Reaction

810.00 N·m
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Static Equilibrium Condition

For a stationary body in static equilibrium, the vector sum of all forces is zero (ΣF = 0) AND the sum of all moments of force about any pivot axis is zero (Στ = 0).

Calculation Methodology & Details

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Formula

Torque Moment: τ = F × r × sin(θ) Pressure: P = F / A Center of Gravity: x_cg = Σ(m_i × x_i) / Σm_i Factor of Safety: FoS = Ultimate Yield Strength / Allowable Stress

Applies static structural equilibrium, method of joints/sections for truss members, and solid mechanics stress-strain Hookean relations.

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Important Disclaimer

Calculations assume non-deformable rigid bodies in static non-accelerating reference frames unless material elasticity values (Young's modulus E) are provided.

How to Calculate Step-by-Step

Follow these steps to complete the calculation:

1

Step 1

Enter applied point load F (N) or distributed load w (N/m).

2

Step 2

Specify beam span length L, support pin/roller locations, or cross-sectional area A.

3

Step 3

View support reaction forces (R_A, R_B), torque moment in N·m, center of gravity coordinates, or Factor of Safety (FoS).

Detailed Insights & Expert Guide

ℹ️ About this Calculation

The Static Friction Calculator computes beam reaction forces, truss member axial forces, center of gravity location, torque moments, PSI pressure conversions, and structural engineering safety factors.

Variable Glossary

Input

Moment Arm (r)

Perpendicular distance from the line of action of force to the pivot center.

Parameter

Factor of Safety (FoS)

Ratio of ultimate material load capacity to maximum expected operational load (FoS > 1 required).

FAQ

How are beam support reactions calculated for simply supported beams?
Take moments about support A: ΣM_A = 0 ⟹ R_B = (F × d) / L. Then sum vertical forces: ΣF_y = 0 ⟹ R_A = F - R_B.
What is the difference between Center of Mass and Center of Gravity?
Center of mass is the mean location of mass distribution in space. Center of gravity is the point where the net gravitational force acts. In uniform gravitational fields (like Earth's surface), both points are identical.
What is reduced mass in a two-body system?
Reduced mass μ = (m₁ × m₂) / (m₁ + m₂) simplifies a two-body interaction problem into an equivalent single-body problem in orbital mechanics and molecular vibrations.