MOI (Multiplicity of Infection) Calculator

Calculate the Multiplicity of Infection (MOI) or determine the required volume of viral stock needed for a target cell count.

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Infection Parameters

Select calculation mode and enter host cell/viral stock values.

Actual MOI

1.000
Poisson distribution breakdown:
  • Uninfected (P₀): 36.8%
  • Single virion (P₁): 36.8%
  • Multi-infected (P₂₊): 26.4%
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High vs. Low MOI Strategy

Use MOI $ge 5$ to ensure $> 99%$ of cells are transduced simultaneously. Use low MOI ($le 0.1$) for single-copy lentiviral integration screens.

Poisson Infection Probabilities by MOI Reference Table

Multiplicity of Infection (MOI) Uninfected P(0) Exactly 1 Virion P(1) Multiple Virions P(≥2)
MOI = 0.1 90.48% 9.05% 0.47%
MOI = 1.0 36.79% 36.79% 26.42%
MOI = 3.0 4.98% 14.94% 80.08%
MOI = 5.0 0.67% 3.37% 95.96%

Methodology & Equations

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MOI Equation

MOI = (Viral Titer × Virus Vol) / (Cell Conc × Cell Vol)

Calculates average number of plaque forming units (PFU) per host cell.

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Poisson Stochastic Distribution

P(k) = (e^(-MOI) · MOI^k) / k!

Determines exact proportion of cells infected by $k$ viral particles.

Frequently Asked Questions

What is Multiplicity of Infection (MOI)?

MOI is the ratio of infectious agents (e.g., viral particles or bacteria) to target infection cells: $text{MOI} = {text{Total Virus Particles (PFU)}}{text{Total Host Cells}}$.

How does the Poisson distribution relate to MOI?

Because viral entry into cells is a random stochastic process, the probability of a cell receiving $k$ virions follows a Poisson distribution: $P(k) = {e^{-text{MOI}} cdot text{MOI}^k}{k!}$.

Why do ~36.8% of cells remain uninfected at MOI = 1?

At an average MOI of 1, $P(0) = e^{-1} approx 0.368$ (36.8%) of cells escape infection, while 36.8% receive exactly 1 virus and 26.4% receive multiple viruses.

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