Clausius-Clapeyron Calculator

Calculate the vapor pressure at a second temperature or the enthalpy of vaporization using the Clausius-Clapeyron relation.

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Calculation Parameters

Specify your stoichiometry inputs.

0.1 kPa500 kPa
-50 °C300 °C
1 kJ/mol100 kJ/mol
-50 °C300 °C

Calculated Result

Calculated Vapor Pressure P2

3.17 kPa
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Expert Tip

This relation assumes the enthalpy of vaporization is independent of temperature, which is highly accurate for small temperature ranges.

How this Calculator Works

This calculator computes the vapor pressure (P2) at a second temperature (T2) based on the Clausius-Clapeyron equation. Adjust parameters below:

  • Vapor Pressure P1: Reference pressure in kPa (Default: 101.3 kPa)
  • Temperature T1: Reference temperature in °C (Default: 100 °C)
  • Enthalpy of Vaporization (ΔHvap): Energy to vaporize 1 mole of liquid in kJ/mol (Default: 40.7 kJ/mol)
  • Temperature T2: Target temperature in °C (Default: 25 °C)

The results are computed instantly and updated in the results panel on the right.

Formula & Methodology

P2 = P1 * exp( - (ΔHvap * 1000 / R) * (1 / T2 - 1 / T1) )

Where:

  • P1, P2: Vapor pressures at absolute temperatures T1 and T2 (Kelvin).
  • ΔHvap: Enthalpy of vaporization (J/mol, converted from kJ/mol).
  • R: Ideal gas constant (8.314 J/mol·K).

Step-by-Step Calculation Example

To calculate the vapor pressure of water at 25°C manually, follow these steps:

  1. Identify the input parameters. For example:
    • P1 = 101.3 kPa, T1 = 100°C (373.15 K)
    • ΔHvap = 40.7 kJ/mol = 40700 J/mol
    • T2 = 25°C (298.15 K), R = 8.314 J/mol·K
  2. Apply the formula:
    P2 = 101.3 * exp( - (40700 / 8.314) * (1/298.15 - 1/373.15) ) P2 ≈ 101.3 * exp(-3.465) ≈ 3.17 kPa
  3. Verify the calculated value which is updated instantly in the results panel on the right.

Frequently Asked Questions

What is the Clausius-Clapeyron equation?

ln(P2 / P1) = (-ΔHvap / R) × (1/T2 - 1/T1), relating vapor pressure changes to absolute temperature and enthalpy of vaporization.

What is ΔHvap?

ΔHvap is the molar enthalpy of vaporization, representing energy required to transform 1 mole of liquid into gas at constant pressure.

Why does liquid boiling point decrease at high altitudes?

Atmospheric pressure P is lower at high altitudes; according to Clausius-Clapeyron, lower external pressure reduces the temperature needed for vapor pressure to match atmospheric pressure.

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